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How can I access a list by index in Haskell, analog to this C code?

int a[] = { 34, 45, 56 };
return a[1];
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Look here, the operator used is !!.

I.e. [1,2,3]!!1 gives you 2, since lists are 0-indexed.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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