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在DolphinDB database中有下面代码:

x1='{"name":"","form":"scalar","type":"double","value":"2.1E+5"}'
x2='{"name":"","form":"scalar","type":"double","value":"100"}'
t=table(1..2 as id,[x1,x2] as val)
typestr(fromJson(x1)) //DOUBLE
select id,fromJson(val) from t

执行最后一行语句时,提示

The data form is not supported

请问可以用什么方法解决?


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1 Answer

fromJson不能接受向量作为参数,可以用each函数来实现:

x1='{"name":"","form":"scalar","type":"double","value":"2.1E+5"}' 
x2='{"name":"","form":"scalar","type":"double","value":"100"}' 
t=table(1..2  as id,[x1,x2] as val)

select id,each(fromJson,val) from t

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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