Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have a syntax error in the following line. However I can't understand what is the reason of this error.

if (address1.compareTo(address2) = 1)
        System.out.println(address1 + " is greater than " + address2);

What I want to achieve is printing proper message if and only if compareTo returns 1.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
461 views
Welcome To Ask or Share your Answers For Others

1 Answer

You should compare (==) instead of assigning (=). It can be very dangerous! To avoid such situations you can use Yoda notation so instead of comparing

address1.compareTo(address2) == 1

You can compare:

1 == address1.compareTo(address2)

In case of missing =, there will be comparation error.

In your case, it would be better to compare:

address1.compareTo(address2) > 0

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...