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I have two Vecs that correspond to a list of feature vectors and their corresponding class labels, and I'd like to co-sort them by the class labels.

However, Rust's sort_by operates on a slice rather than being a generic function over a trait (or similar), and the closure only gets the elements to be compared rather than the indices so I can sneakily hack the sort to be parallel.

I've considered the solution:

let mut both = data.iter().zip(labels.iter()).collect();
both.sort_by( blah blah );
// Now split them back into two vectors

I'd prefer not to allocate a whole new vector to do this every time because the size of the data can be extremely large.

I can always implement my own sort, of course, but if there's a builtin way to do this it would be much better.

See Question&Answers more detail:os

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I just wrote a crate "permutation" that allows you to do this :)

let names = vec!["Bob", "Steve", "Jane"];
let salary = vec![10, 5, 15];
let permutation = permutation::sort(&salary[..]);
let ordered_names = permutation.apply_slice(&names[..]);
let ordered_salaries = permutation.apply_slice(&salary[..]);
assert!(ordered_names == vec!["Steve", "Bob", "Jane"]);
assert!(ordered_salaries == vec![5, 10, 15]);

It likely will support this in a single function call in the future.


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