javascript：if在条件为false的情况下仍然执行代码是为什么？

Question

asked Jan 24, 2021 in Technique[技术] by 深蓝 (71.8m points)

条件为changeNum !== undefined && changeNumIndex !== undefined,
p1为执行成功的现象，p2为我复制条件过去重新执行，但是发现执行失败。

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1 Answer

深蓝 · Answer 1 · 2021-01-23T23:48:28+0000

answered Jan 24, 2021 by 深蓝 (71.8m points)

findIndex返回-1不是undefined。你这是chrome的调试？

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