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求一个正则表达式,用来替换字符串

$str = 'SELECT userid, username FROM t WHERE user_lock=1';

将SELECT和FROM之间的部分替换成COUNT(*)

$newstr = 'SELECT COUNT(*) FROM t WHERE user_lock=1';

SELECT和FROM可能是大写或小写

userid, username不固定也可能是其他的字符串

$str = 'SELECT id,other FROM t WHERE user_lock=1';


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我JS这么写的,你替换一下吧,
正则部分为

/SELECT|select.*?FROM|from/
"SELECT id,other from t WHERE user_lock=1".replace(/SELECT|select.*?FROM|from/,"SELECT COUNT(*) FROM")

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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