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mongodb针对字段值一样是怎样排序的,需要查找某个字段并且按照id来排序,数据:

[
{_id:1,status:"A"},
{_id:2,status:"A"},
{_id:3,status:"C"},
{_id:4,status:"A"},
{_id:5,status:"A"},
{_id:6,status:"B"},
{_id:7,status:"B"},
{_id:8,status:"A"},
...
]

直接用_id排序:

db.list.find({status:"A"}).sort({_id:-1}).limite(10)

达到效果,但扫描量大.


在status上创建索引(正向),查询:

db.list.find({status:"A"}).sort({status:-1}).limite(10)

达到效果,发现和_id排序一致,但是这种排序无法比较,字段都是"A",结果是怎样来的,是根据_id的还是mongodb默认的排序,更新,删除,创建新的数据好像都不影响排序.

所以能不能使用上面的方法排序,还是需要创建一个复合索引{status:1,_id:1}.


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扫描量大是怎么回事?

db.list.find({status:"A"}).sort({_id:-1}).limite(10)

你就给status加个索引,然后用这个查询不行吗


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