Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have a table with two columns that might be null (as well as some other columns). I would like to count how many rows that have column a, b, both and neither columns set to null.

Is this possible with Oracle in one query? Or would I have to create one query for each? Can't use group by or some other stuff I might not know about for example?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
710 views
Welcome To Ask or Share your Answers For Others

1 Answer

COUNT(expr) will count the number of rows where expr is not null, thus you can count the number of nulls with expressions like these:

SELECT count(a) nb_a_not_null,
       count(b) nb_b_not_null,
       count(*) - count(a) nb_a_null,
       count(*) - count(b) nb_b_null,
       count(case when a is not null and b is not null then 1 end)nb_a_b_not_null
       count(case when a is null and b is null then 1 end) nb_a_and_b_null
  FROM my_table

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...